2007-02-11 22:51:11 · 5 answers · asked by rohitvijaysharma 1 in Science & Mathematics ➔ Physics
the escape velocity of earth is the minimum velocity required to get out of this place :)
The values in various measurements are the following :
11100 m/s
40200 km/h
25000 mi/h
All the values are approximate only, acct to different conditions of launching and weather conditions and even difference in wind resistance can slightly vary the velocity a bit..
2007-02-11 22:56:14 · answer #1 · answered by Kiran 2 · 0⤊ 0⤋
It is approximately 11 kilometres per second.
You can work it out by using-:
Escape Velocity = square root (2GM / r)
where G is the Gravitational constant.
M is the Mass of the Earth (or whatever body you are escaping from)
r is the radius of the body.
2007-02-11 23:12:01 · answer #2 · answered by Gnomon 6 · 0⤊ 0⤋
It is approximately 11 kilometres per second.
You can work it out by using-:
Escape Velocity = GMm / r
where G is the Gravitational constant.
M is the Mass of the Earth (or whatever body you are escaping from)
m is the mass of the object trying to escape
r is the radius of the body.
2007-02-11 22:58:58 · answer #3 · answered by Doctor Q 6 · 0⤊ 1⤋
28 m/s
2007-02-11 23:57:12 · answer #4 · answered by supremecritic 4 · 0⤊ 0⤋
Dunno but anthing that can break a 10Newton force (ie gravity)
for consistently long enougth to reach past the atmosphere
will 'escape'
2007-02-11 22:59:26 · answer #5 · answered by Banderes 4 · 0⤊ 0⤋