In the diagram, AB=9 and AD=8. Two circles, centers E and F are tangent to each other and to X and M and N and Y respectively. If the radius of the smaller circle is 2, find the radius of the larger circle.
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2007-02-11 22:42:22 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
In short the answer is 3.
Resolve the diagram into vertical and horizontal components.
AB = XE + FN + (horizontal component of EF)
AD = ME + FY + (vertical component of EF)
(Hint: The line EF is approx 36.87 degrees from horizontal.)
2007-02-12 00:02:49 · answer #1 · answered by Mark G 1 · 0⤊ 0⤋
the answer seems to be
x^2 - 30x + 89 = 0
but it seems i cant solve the equation here x is the radius of the larger circle
do u need explations as to how i got the answer ? let me know
ill give u he basic equation i derived from
[ 7-x ] ^2 + [ 6-x ] ^2 = [ x+2 ] ^2
here x+2 is the distance betn E and F
and 7-x and 6-x r the other two sides or a right angle triangle
2007-02-12 08:23:29 · answer #2 · answered by sas35353535 7 · 0⤊ 0⤋
4...I think. But don't ask me how I got it because I guesses. But I think that is the correct answer. Let me know if it is correct.
2007-02-12 06:46:01 · answer #3 · answered by <3Aja*Marissa*Ashley<3 2 · 0⤊ 0⤋
3 or 3.5...
2007-02-12 07:50:21 · answer #4 · answered by pinaakee 2 · 0⤊ 0⤋