I'm really struggling on this math problem, think you can help?

Question

E F 6
x D 7
=
DDFD
+JED
=
HGED


Each letter represents a different digit.

Answer 1

obviously D=2...

E= 3
F=1
G=5
H=8
J=6

Answer 2

I THINK (i may not be right) that this question is not possibly solvable, here's why:

I will call all the values I don't know '?'

The answer to:
E F 6
x D 7
ends with 2 because 7*6 = 42.

From:
DDFD
+JED

we understand that D + D = ?2 (since the last digit is two -- from the first one)

so the two possible values for D are 1 and 6.

If D = 1, then D + D = 2 this is correct according to what we have so far. So D = 1 is a possibility.

if D = 6, D + D = 12, this is still correct, so D = 6 is also a possibility.

Now lets use parts two and three of the provided information
DDFD
+JED
=
HGED

according to this D + D = 10(?) + 1(D)

if we assume that D = 1, D+D = 2. but when we substitute B in the right hand side of the equation, we get: 1(2) = 10(?) + 1(1) for no value of ? will this equation be true, thus we eliminate D = 1.

If we go with D = 6, D + D = 12. and 10(1) + 1(2) = 10(?) + 1(6)
and as before, no value of ? will fulfill this equation therefore eliminating all possible solutions of D.

Answer 3

I think there's something wrong with the way the problem is set up. Since you start off with a number ending in 6 times a number ending in 7, the product has to end in 2 (because 7 times 6 is 42, and whatever other caclulations you do for the multiplication, they're not going ot affect the unit's digit in the product). This means D=2. But then we're adding this to another number ("JED") that ends in 2. The result ("HGED") should end in 4, but instead it ends in 2. This is impossible.

Answer 4

I do not think it can be done (99% sure), I just threw a program together to brute force it and it returnd no value.
Searching:
6*7=0+0 (42) = (0)
6*7=0+0 (42) = (0)
6*7=0+0 (42) = (0)
6*7=0+0 (42) = (0)
6*7=0+0 (42) = (0)
6*7=0+0 (42) = (0)
...
996*97=9999+999 (96612) = (10998)
996*97=9999+999 (96612) = (10998)
996*97=9999+999 (96612) = (10998)
996*97=9999+999 (96612) = (10998)
996*97=9999+999 (96612) = (10998)



E F 6
x D 7
=
DDFD
+JED
=
HGED

"obviously D=2...

E= 3
F=1
G=5
H=8
J=6"

316 * 27 (8532) = 2212+632(2844)

Answer 5

what you do is multiply 6 by 7= 42
so you know definately F=2
and D7=27
and DDFD=22F2
you check between 2202 to 2292 ( since F is a digit between 0 and 9) which if you divide by 7 will give you an answer without remainder ( you have multiply 7 by EF6 to give DDFD or 22F2)

the answer is if you divide 2212 by 7 you get 316
therefore D=2, F=1 and E=3

316
x27
____
2212
632
____
8532


so H=8 and J=6 G=5
E=3 F=1 and D=2

Answer 6

Impossible D would have to be 0 and 2; Try again.

Answer 7

i think something is wrong with this prob.
since 6*7 is 42.therefore D=2.but subsiting this u can understand that the prob mite be wrong