when f(x)=5x^2+4 g(x)2x-3
2007-02-11 17:49:26 · 3 answers · asked by jessica h 1 in Science & Mathematics ➔ Mathematics
As asked, the question doesn't make any sense. I suspect that you are actually saying:
f(x) = 5x² + 4
g(x) = 2x-3
what is
f(g(h)).
To solve it, substitute h into g(x) for the x to get
g(h) = 2h-3
Then substitute g(h) for x in f(x) to get
f(g(h)) = 5*(2h-3)² + 4 = 5*(4h² - 12h + 9) + 4 or
f(g(h)) = 20h² - 60h + 49
Hope that helps ☺
Doug
2007-02-11 18:02:31 · answer #1 · answered by doug_donaghue 7 · 0⤊ 0⤋
I dont understand the question, either. Sorry. Write to me and I will help you
Ana
2007-02-12 19:49:16 · answer #2 · answered by MathTutor 6 · 0⤊ 0⤋
wrong, f(h-y) maybe!!However , domain of f = range g, and domain of g = range of f, therefore, g(f(x)) =x and f(g(Y))=y, so plug the equation accordingly, done.!!
2007-02-12 02:03:20 · answer #3 · answered by Anonymous · 0⤊ 0⤋