I need help on math please?

Question

the problem is like this
x-13 3x-3
------------ + -------------
x^2-x-12 x^2-x-12

can I get some help please
this is not setting up like I wanterd so
it is x-13 over x^2-x-12 + 3x-3 over x^2-z-12
I hope that did not make it to confusing

Answer 1

If you meant:

{x-13} /{x^2-x-12} + {3x -3}/{x^2-x-12} then since the denominators are identical you simply add the numerators to get

{4x-16}/{x^2-x-12} which can be further reduced to:

4*{x-4}/{x-4}{x+3} the x-4 terms cancel and you are left with

4/{x+3}

Answer 2

You mean:
(x-13) / (x^2 - x - 12) + (3x-3) / (x^2 - x - 12)

Since the denominators are the same, we can do the addition of the numerators first:
(x-13+3x-3) / (x^2 - x - 12) = (4x-16) / (x^2 - x - 12)
____________________ = 4(x-4) / (x-4)(x-3) = 4/(x-3)

Or another way as you represented above:

4
----
x-3

Answer 3

you have to add the numerators cause the denominators are equal:
(x-13)+(3x-3)=4x-16
take out 4:
4(x-4)
note that this is over x^2-x-12 which can be factored:
x^2-x-12=(x+3)(x-4)
so you have:
4(x-4)
_____

(x+3)(x-4)
simplify and get:
4
___

x+3
Hope that helps=D

Answer 4

since the denominators of both sides are same (x^2-x-12), you just simply add the numerators

(x-13) + (3x-3) = 4x -16 = 4(x-4)

simplify the denominator and you get

x^2-x-12 = (x-4)(x+3)

so you get the answer

4(x-4)
-------------
(x-4)(x+3)

therefore the final answer is

4
-------
(x+3)