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Thanks in advance.

2007-02-11 17:31:27 · 4 answers · asked by drjoestan 1 in Science & Mathematics Mathematics

4 answers

Look at 1/x...as x goes bigger (tends toward infinity), it's value goes smaller (tends toward 0).

Then, x^(1/x) tends toward x^0 which is 1.

2007-02-12 01:09:28 · answer #1 · answered by Anonymous · 0 0

First the exponential on 1/x , x can not be 0 therefore it s limit is 1.so x^1is 1. proof
As you graph y=x^1, it gives you an asymtote like line at (x,y)=(1,1), if you aproach from (-) infinity it will be one,if you aproach from the (+ )infinity is 1,simple the line y=1.

2007-02-11 17:36:42 · answer #2 · answered by Anonymous · 0 0

As x goes to infinity, 1/x gets closer and closer to zero. Any number no matter how large when raised to the zero power = 1

2007-02-11 17:36:56 · answer #3 · answered by Phoenix 1 · 0 1

Ln(x^(1/x) =
Lim (Ln(x))/x =
x→∞

lim (1/x) = 0
x→∞
so
Lim (Ln(x))/x = 0
x→∞
and
Lim (x^(1/x)) = e^0 = 1
x→∞

2007-02-11 17:44:05 · answer #4 · answered by Helmut 7 · 1 0

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