10 points for the first answer I get that works! Is (delta)G^0 always constant for a given reaction?

Question

I ask this because I am asked to find the equilibrium constant K for the reaction N2 + O2 --> 2NO when the temperature is 1100 degrees Celsius. Given that (delta)G^0 for the reaction at 25 degrees Celsius is 173.4 kJ/mol. I thought that I could use the equation (delta)G^0 = - RT ln K , because the (delta)G^0 is still 173.4 for it at this new temperature . .

Answer 1

You could always try deltaG =deltaH - TdeltaS. This would give you a very different value of deltaG at the higher temperature. The only assumption that you would have to make is that deltaH and deltaS didn't change much with temperature, and I believe that this is true.