help! any math experts here?

Question

how do you find the distance between points (3,7) and (8,7)? my math teacher gave me like a formula to solve this but i don't understand it! can somebody teach me step by step? i'll give 10 points!

Answer 1

In this case it's easy, the y coordinates are the same. So the distance is the difference of the x coordinates.

Distance = 8 - 3 = 5

The more general formula, when neither coordinate is the same is:

Distance = √{(x1 - x2)² + (y1 - y2)²}

In this case that would be

Distance = √{(3 - 8)² + (7 - 7)²} = √{(-5)² + 0²} = √25 = 5

Answer 2

Since the last points have 7 then you just find the difference between the two first ones which is 5. 8-3=5 It might be easier if you drew a diagram like this.
7 OOOOOOOO
6 OOOOOOOO Match the points. 3 across and 7 up then
5 OOOOOOOO 8 across and 7 up. How many dots are (3,7)
4 OOOOOOOO and (8,7) far from each other? 5 dots.
3 OOOOOOOO
2 OOOOOOOO
1 OOOOOOOO
0 1 2 3 4 5 6 7 8

Answer 3

Resolve this to the difference in x and y component.The difference between x component is 8-3=5,The difference between y component is 7-7=0.By phytagorean theorem a2+b2=c2,then 5 raised to the power of 2 is 25 and 0 raised to the power of 2 is 0.Then 25+0=25.That is why the formula is (x1-x2)2+(y1-y2)2=distance2

Answer 4

the formula is like the pythagorean formula (a^2+b^2=c^2)
so if you think about it, your drawing a right triangle using those two points as a hypotenous
the (y2-y1) and (x2-x1) part is just finding the other two sides
so plug in numbers and get this:
SQRT((7-7)^2+(8-3)^2)
innermost parentheses first:
SQRT((0)^2+(5)^2)
square:
SQRT(0+25)
add
SQRT(25)
and take the square root:
5
hope that helps =D

Answer 5

the distance formula is
d= square root (xsub2 - xsub1)^2 + (ysub2 - ysub1)^2

note: incase you don't know, ^2 means squared so 3^2 = 3x3 = 9

in your problem you have (3, 7) and (8,7)

xsub2 = 8
xsub1 = 3
ysub2 = 7 (the second 7)
ysub1 = 7 (the first 7)

so if you plug all this in, you will get

d = square root (8-3)^2 - (7-7)^2

d = square root (5)^2 - (0)^2

d = square root 25

d = 5

I hope you can understand this =]

Answer 6

Question is (3,7) and (8,7)
Distance is 5 (8-3)

Answer 7

distance = z

z^2 = x^2 + y^2

so

x^2 = (x2 - x1)^2 = (8-3)^2 = 5^2 = 25

y^2 = (y2 - y1)^2 = (7-7)^2 = 0^2 = 0

therefore

z^2 = 25 + 0 = 25

z = 5

Answer 8

I think its the formula for finding a triangle

Distance between 2 coordinates

would be the square root of the sum of [ (Y2-Y1)square + (X2-X1)]

Answer 9

you do the square root of (8-3)^2 + (7-7)^2 which turns out to be 4

Answer 10

A and B are the two points in the plane .
A(x1,y1)=(3,7)
B(x2,y2)=(8,7)
AB=square root of(x2-x1)the whole square+(y2-y1)the whole square.
the square root applies for both (x2-x1) and (y2-y1)