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(y^2-16)/(y^2+16)

2007-02-11 16:32:20 · 6 answers · asked by Anonymous in Science & Mathematics Mathematics

Old joke.
And my mom is dead @$$hole.

2007-02-11 16:35:57 · update #1

POSSIBLE ANSWERS:
4
-4
ALL REAL #S
NONE

2007-02-11 16:38:29 · update #2

6 answers

in order for the expression to be undefined the denominator needs to be 0, as anything over 0 is undefined.

y^2 + 16 =0
y^2 = -16

no real solutions..

for imaginary solutions y needs to be +/- 4*sqrt(-1)

y = +/- 4i

2007-02-11 16:37:32 · answer #1 · answered by radne0 5 · 0 0

the reply would prefer to be imaginery. you positioned the denominator =0 because you won't be able to divide through 0 it truly is undefined. In doing so, you've y^2+16=0 hence y^2=-16 and so the in trouble-free words a danger solutions will be 4i and -4i

2016-11-27 03:00:18 · answer #2 · answered by Anonymous · 0 0

To make it undefined, the bottom has to be zero, so solve
y² + 16 = 0
y² = - 16
y = ±4i.

Can y be a complex number? If only real, the expression will not be undefined.

2007-02-11 16:36:41 · answer #3 · answered by Philo 7 · 0 0

There can't be a value that will make this expression undefined, because if you plug in any number for the y and square it, you will get a positive number, and add a positive number you will have a positive number again. And you can divide any number by a positive number.

2007-02-11 16:37:30 · answer #4 · answered by siran357 1 · 0 0

Your choices do not include the correct answer, which is y = ± i4

2007-02-11 16:46:35 · answer #5 · answered by Helmut 7 · 0 0

your mom.

2007-02-11 16:34:38 · answer #6 · answered by democrat13 2 · 0 0

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