I need help with
4y-1/2y^2+5y-3 - y+3/ 6y+y-2 I know that I'm using Subtracting rational expressions, but I can't seem to factor the denomators.
2007-02-11 16:11:12 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
It's been awhile for me but I'd do it this way. Better check my addition and subtraction as I did it in my head!
4y-1/2y^2+5y-3 - y+3/ 6y+y-2
Multiply through by 2
8y-y^2+10y-6-2y+y+2y-4
Reorder
8y+10y-2y+y+2y-y^2-6-4
Compile
19y-y^2-10
2007-02-11 16:25:55 · answer #1 · answered by Anonymous · 0⤊ 0⤋
from what it looks like you mean the
1st denominator is 2y^2+5y-3
that factors to (2y-1)(y+3)
the 2nd is 6y^2+y-2???
that factors to (3y+2)(2y-1)
2007-02-12 00:22:17 · answer #2 · answered by dla68 4 · 0⤊ 0⤋
Can you repost with more parentheses? I'm not sure which parts are supposed to be denominators.
Thanks.
2007-02-12 00:15:55 · answer #3 · answered by Doc B 6 · 0⤊ 0⤋