vector A has magnitude of 8 and points in the positive x-direction. Vector B has magnitude of 23 and makes an angle of 39degree with the positive x-axise
--- What is the magnitude of A-B
2007-02-11 12:45:49 · 3 answers · asked by i.p 1 in Science & Mathematics ➔ Physics
This is a little easier to conceptualize if you take it as -B+A. If you put A and B tail to tail, the resultant vector -B+A goes from the head of B to the head of A. So it can be thought of as the third side of a triangle. Solve using the Law of Cosines.
(-B+A)² = A² + B² - 2AB cos39° = 8² + 23² - 2*8*23 cos39°
≈ 17.52
2007-02-11 13:02:48 · answer #1 · answered by Northstar 7 · 0⤊ 0⤋
If you sum the vectors in the x direction, you get -9.87. Summing the vectors in the y direction will get you -14.47. To find the magnitude, use Pythagorean Theorem, and you should get 17.5.
2007-02-11 20:55:05 · answer #2 · answered by bradiieee 2 · 0⤊ 0⤋
???
2007-02-11 20:48:13 · answer #3 · answered by Anonymous · 0⤊ 2⤋