Multiply one of the equations by a number so that when you add them up they equal to 0. Since the second one has a negative 8, I multiplied the first one by 4 so that the second y equals positive 8 and the y's cancel.
3x+2y=3
9x-8y=-2
(4)3x+(4)2y=(4)3 SO 12x+8y=12
9x -8y= -2
12x+8y=12
9x -8y= -2
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21x=10
x=10/21 <-----
Since you know the x, now you can solve for y by plugging it into either one of the equations. I picked the first one.
3(10/21)+2y=3
10/7 +2y = 3
2y = 11/7
y=22/28 = 11/14 <-----
Check your answer
3(10/21)+2(11/14)=3
9(10/21)-8(11/14)=-2
If you work them out or plug them both into your calculator they should be correct.
2007-02-11 10:16:20
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answer #1
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answered by Anonymous
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Since 3x+2y=3 you can rearrange this equation to find out what x is and then eliminate it in the other equation.
subtracting 3x from both sides of first equation gives you 2y=3-3x so y= 3/2 - 3/2x. Now put that in the other equation where y is.
You get 9x-8(3/2-3/2x)=-2. When you combine similar terms you get 9x-12-12x=-2. Further combining you get 9x-12x=-2+12 or -3x=10. Divide both sides by 3 and you get x=-10/3
Now that you know x put it back in the first equation to get y. You will have 3(-10/3)+2y=3. Now you combine to get -10+2y=3 or 2y=-7. When you divide both sides by 2 you get y=-7/2
Now you have x and y.
2007-02-11 10:03:27
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answer #2
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answered by Rich Z 7
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3x+2y=3 and 9x-8y=-2
multiply 3x+2x+3 all by 4, to cancel out the y variable.
12x+8y=12 add the 2 equations
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9x-8y=-2
21x=10
x=10/21
substitute the x into one of the equations to get y.
2007-02-11 09:55:56
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answer #3
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answered by desirooo58 3
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Multiply equation throughout by 3 so yoy can subtract and eliminate x
then subtrace equation 2 from new equation 1
14y = 11
y = 11/14
then substitute the answer into one of the original equations to find x
2007-02-11 10:01:03
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answer #4
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answered by sparbles 5
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if the equation is right, then x would have to be 0.47619 and y would have to be 0.785715. that is if the equation is rite.
2007-02-11 10:01:47
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answer #5
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answered by sparkie 2
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