What would the acceleration and tension be?

Question

Two blocks on a horizontal frictional surface, and the coefficient of kinetic friction between each block and the surface is 0.1, what would be the acceleration? what would be the tension in the string?

The picture looks like:

[5.47 kg]---T---[19.5 kg]---48.8 N--->

The [ ] areas are the blocks.
The ---T--- is the tension.
The ---48.8---> is the force.
Acceleration of Gravity is 9.8

the first post for the answer is wrong

Answer 1

F=ma
48.8=(24.97)a
a=1.95
first block doesnt matter for tension
f=un
f=.1(5.47*9.8)
f=5.36N

Answer 2

Both blocks have frictional forces resisting the motion. The total frictional force
Ff = u*(5.47 kg + 19.5 kg)*g = 24.5 N

The remaining force available to accelerate the 2 blocks is
Fnet = 48.8 N - 24.5 N = 24.3 N
The 2 blocks therefore accelerate according to
Fnet = (5.47 kg + 19.5 kg)*a
a = 0.97 m/s^2

Now look in detail at the smaller block. The net force on this smaller block can be found from
Fnetsmall = 5.47 kg*a
Fnetsmall = 5.47 kg*a = 0.97 m/s^2 = 5.31 N

The net force is the resultant of the force of the tension pulling to the right and its friction, a force to the left.

Ffsmall = u*5.47 kg*g = 5.36 N

Fnetsmall = T-Ffsmall or
T = Fnetsmall + Ffsmall
T = 5.31 N + 5.36 N = 10.67 N