Speed of light c = 3 x 10^8 m/sec, and g = 9.8 m/sec^2. What's the gravitational pull 1/2 meter above the surface of a black hole of event horizon size of 1 meter? I got the figure of about 10,000,000,000,000,000 g's. Now, does that seem high? Refute please?
2007-02-11 09:15:19 · 3 answers · asked by Scythian1950 7 in Science & Mathematics ➔ Physics
I'm sure many are going to say, "Whoa, it can't be that high", but that's not what I'm asking for. If it's not that high, what is it supposed to be, and why?
2007-02-11 09:21:38 · update #1
Gravitational constant
G = 6.7 x 10^-11 m^3 / (sec^2 kg)
2007-02-11 09:26:54 · update #2
Schwarzchild radius is given by:
R = 2GM / c²
while acceleration is given by:
a = GM / r²
Source: various
2007-02-11 10:36:47 · update #3
No, it doesn't seem high. The gravitational pull of a black hole inside the event horizon has to be so strong it can contain even light. 10^16 g's isn't that surprising, considering the gravitational force will be 4 times as strong there as it would at the edge of the event horizon.
2007-02-11 09:28:22 · answer #1 · answered by J 2 · 0⤊ 0⤋
Yes.
2007-02-11 17:19:20 · answer #2 · answered by Lindsay Jane 6 · 0⤊ 1⤋
What equations did you use to achieve this answer?
2007-02-11 17:33:47 · answer #3 · answered by pluto035 3 · 0⤊ 0⤋