A rocket is fired at a speed of 75.0 m/s from ground level, at an angle of 56.9° above the horizontal. The rocket is fired toward an 11.0 m high wall, which is located 25.0 m away. The rocket attains its launch speed in a negligibly short period of time, after which its engines shut down and the rocket coasts. By how much does the rocket clear the top of the wall?
2007-02-11 08:10:13 · 2 answers · asked by allyn_03 2 in Education & Reference ➔ Homework Help
Not enough data to make any 'real' calculation. No way you can calculate the drag on the rocket so there is no way you can calculate what trajectory the rocket has. Just assume it is a straight line.
Calculate what the height on a triangle with a 56.9 degree angle is at 25.0 m. Subtract the 11.0 m of the wall and you are done.
2007-02-11 08:19:15 · answer #1 · answered by Puppy Zwolle 7 · 0⤊ 0⤋
If you cannot do this using Trig then draw a scale drawing and work it out that way.
2007-02-11 16:13:50 · answer #2 · answered by blues_m1 2 · 0⤊ 0⤋