A 6kg concreate block is dropped from a top of a tall building.The block has fallen a distance of 55m and has?

Question

a speed of 30 meters when it hits the ground?

A. at the instant the block was released what was its gravitational potential energy with respect to the ground.

b.what is the kinetic energy
c how much mechanical energy was lost by the block as it fell
d what happen to the mechanial energy lost by the block

Answer 1

PE=mgh
PE=(6)(9.8)(55)
PE=3234j
KE=.5mv^2
v is 0 in beginning, so KE is 0
KE=.5(6)(30^2)
KE=2700j
energy lost =3234j-2700j
=534j
lost to air resistance