weight is the force by which earth attracts a body towards its centre. so if a body is at centre, is its weight zero because its now not being attracted towards anything.
or is its weight maximum, because the value of 'g' is inversely realted to the distance from radius of the earth 'R'??
2007-02-11 05:59:33 · 6 answers · asked by last 1 in Science & Mathematics ➔ Physics
Zero. At the precise center of the earth, you would equally attracted in every direction. These forces would cancel out giving you a net force of zero.
2007-02-11 07:39:37 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Lets say you hollowed out a big sphere in the center of the Earth and a person was able to be in the exact center, surviving the heat and the pressure, that person would float weightless. All forces balance out - the gravity exerted by the earth above you is cancelled out by the same amount below and you float weightless
The inverse square rule of distance/strength for g applies to distance away from an object.
2007-02-11 06:13:05 · answer #2 · answered by mytraver 3 · 0⤊ 0⤋
Remeber though, Weight is Mass x Gravitational Strength and therefore at the centre of the Earth be zero.
You would still have mass though !!
2007-02-12 21:54:03 · answer #3 · answered by Doctor Q 6 · 0⤊ 0⤋
the answer will be zero...
the rule that says inverse relation is only till the surface of the earth....after crossing the surface,as the radius grows smaller---the g WILL START DECREASING...PLZ TAKE CARE OF THIS FACT...it comes by that formula(hope u remember it)...
it will reach its minimum at the core,ie,it will be 0 as radius will be 0....hence
answer is zero
2007-02-11 06:35:56 · answer #4 · answered by catty 4 · 0⤊ 0⤋
Maximum. Because it is getting pressure from every direction.
2007-02-11 06:09:07 · answer #5 · answered by oldmanwitastick 5 · 0⤊ 1⤋
zero
2007-02-11 06:05:15 · answer #6 · answered by Anonymous · 1⤊ 0⤋