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Mr.Heijmans refuses to pick up the tab for lunch unless everyone orders at the same time. Unfortunately, the two Amanda's lost track of time and now must run from Le Chateau. Amanda one runs at a speed of 2.5 m/s for 75 s, while Amanda two strolls second half at 3.5 m/s, how long does it take her to reach Mr. Greenjeans from Le Chateau?

2007-02-11 05:41:35 · 1 answers · asked by avant1991 3 in Science & Mathematics Physics

my bad heres the whole question: Mr Heijmans refuses to pick up the tab for lunch unless everyone orders at the same time. Unfortunately, the two Amandas lost track of time and now must run from Le Chateau. Amanda one runs at a speed of 2.5 m/s for 75 s, while Amanda two strolls along at 0.5 m/s for half the distance to the restaurant. if amadanda two runs the second half at 3.5 m/s, how long does it take her to reach Mr.Greenjeans from Le chateau?

2007-02-11 05:55:50 · update #1

1 answers

You made some typos, so we can't do the whole thing for you and be sure we're right.

However, my GUESS as to what you need is this:

Multiply 75*2.5 to get how many meters Amanda 1 went.

Do something to find out how many meters Amanda 2 went (perhaps just divide that by 2, depending on the exact statement of the problem).

Divide that distance (in meters) by 3.5 m/s to get the number of seconds Amanda 2 took.

2007-02-11 05:50:16 · answer #1 · answered by Curt Monash 7 · 0 0

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