the solution should be presented with x first, the correct inequality symbol, then the number
3x + 1 - 8x > 2 (x -5)
I cant figure this one out
2007-02-11 04:42:46 · 3 answers · asked by chickiejam 1 in Science & Mathematics ➔ Mathematics
*Isolate "x" on one side ... 3x + 1 - 8x > 2(x - 5)
First: elimiante parenthesis - distribute the outer term with the terms in parenthesis....
3x + 1 - 8x > 2(x) + 2(- 5)
3x + 1 - 8x > 2x + (-10)
3x + 1 - 8x > 2x - 10
Sec: combine "like" terms on the left side....
3x - 8x + 1 > 2x - 10
- 5x + 1 > 2x - 10
Third: subtract "2x" from both sides....
- 5x - 2x + 1 > 2x - 2x - 10
- 5x - 2x + 1 > - 10
- 7x + 1 > - 10
*Subtract "1" from both sides....
- 7x + 1 - 1 > - 10 - 1
- 7x > - 10 - 1
- 7x > - 11
Fourth: isolate "x" on one side --- divide both sides by "-7"...
- 7x/-7 > - 11/-7
*When you divide by a negative term - change the inequality sign.
x < 11/7
2007-02-11 05:31:22 · answer #1 · answered by ♪♥Annie♥♪ 6 · 1⤊ 1⤋
Get all the x's to the left side:
3x + 1 - 8x > 2(x-5)
-5x + 1 > 2x - 10 (distribute, combine like terms)
-5x > 2x -11 (subtract 1)
-7x > -11 (subtract 2x)
x < 11/7 (divide by -7 ... remember to flip the sign when you divide by a negative number)
2007-02-11 12:48:58 · answer #2 · answered by Mr. Adkins 4 · 2⤊ 0⤋
3x+1-8x>2x-10
-5x+1>2x-10
-5x+1-1>2x-10-1
-5x>2x-11
-5x-2x>2x-2x-11
-7x>-`11
-7x/-7<-11/-7
x<11/7
greater than sign becomes a less sign because you change when dividing with a negative number
2007-02-11 12:52:01 · answer #3 · answered by Dave aka Spider Monkey 7 · 1⤊ 1⤋