I need a step by step solution to this first order differential equation: 3xy' = (2+xy^3)y . Use u'+2u/x = -1

0 ⤊

y' = dy /dx

2007-02-11 04:36:39 · 3 answers · asked by Anestis 2 in Science & Mathematics ➔ Mathematics

3xy'-2y-xy^4 = 0
Divide by -xy^4,
(-3/y^4)y' + 2/(xy^3) = -1
Substituting u = 1/y^3, we have
u'+2u/x = -1

Can you finish it now?

2007-02-11 05:11:22 · answer #1 · answered by sahsjing 7 · 0⤊ 0⤋

uh yah speek in English pleaz! LOL

2007-02-11 12:40:26 · answer #2 · answered by Dance Gal 2 · 0⤊ 1⤋

It would help if you wrote more detail. It isn't clear from your statement what u is.

2007-02-11 13:00:05 · answer #3 · answered by Curt Monash 7 · 0⤊ 0⤋