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5 answers

Lancenigo di Villorba (TV), Italy

I AGREE NOT WITH PREVIOUS ANSWER.
When I put some potassium iodide in an aqueous solution of an acid and hydrogen peroxide, I see a fast darkening of the medium.
This process is driven by some electrochemical half-reactions, as follows :

-) 2 KI(aq) ---> 2 K+(aq) + I2(aq) + 2e (+0.55 V)
-) H2O2(aq) + 2 H+(aq) + 2e ---> 2 H2O(aq) (+1.77 V)
-) H2O2(aq) ---> O2(g) + 2 H+(aq) + 2e (+0.68 V)

Since the electrochemical potential overwritten you stated you obtain IODINE's vapours instead OXYGEN's bubbles, as follows :

2 KI(aq) + H2O2(aq) + 2 H+(aq)--->
---> 2 K+(aq) + I2(aq) + 2H2O(aq)

Iodine leaves its vapours, it is true!
In effects, you can put a small paper-piece wetted by an aqueous STARCH's solution. Iodine's vapours will overcome onto the paper colouring itself in blackish hue. You confirmed iodine's volatility.

I hope this helps you.

2007-02-11 04:37:08 · answer #1 · answered by Zor Prime 7 · 0 0

Acidified Hydrogen Peroxide

2017-01-18 03:10:08 · answer #2 · answered by ? 4 · 0 1

Iodide ion is a reducing agent only, forcing the hydrogen peroxide to be an oxidising agent. Under aqueous conditions, iodine vapour cannot possibly be produced, but brown iodine solution instead.

H2O2 + 2H+ + 2e- ----> 2H2O
2I- ----> I2 + 2e-

If a gas is produced, it can only be by the separate catalytic decomposition of hydrogen perioxide:

2H2O2 ----> 2H2O + O2.

2007-02-11 04:57:59 · answer #3 · answered by Gervald F 7 · 0 0

Hydrogen peroxide is strong oxidising agent.Its liberated
the nascent oxygen.react with potassium iodide,Iodine
gas will come.

2007-02-11 04:49:13 · answer #4 · answered by VENKATARAMAN K 2 · 0 0

Oxygen

2007-02-11 04:23:37 · answer #5 · answered by Niks 3 · 0 0

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