Lancenigo di Villorba (TV), Italy
I AGREE NOT WITH PREVIOUS ANSWER.
When I put some potassium iodide in an aqueous solution of an acid and hydrogen peroxide, I see a fast darkening of the medium.
This process is driven by some electrochemical half-reactions, as follows :
-) 2 KI(aq) ---> 2 K+(aq) + I2(aq) + 2e (+0.55 V)
-) H2O2(aq) + 2 H+(aq) + 2e ---> 2 H2O(aq) (+1.77 V)
-) H2O2(aq) ---> O2(g) + 2 H+(aq) + 2e (+0.68 V)
Since the electrochemical potential overwritten you stated you obtain IODINE's vapours instead OXYGEN's bubbles, as follows :
2 KI(aq) + H2O2(aq) + 2 H+(aq)--->
---> 2 K+(aq) + I2(aq) + 2H2O(aq)
Iodine leaves its vapours, it is true!
In effects, you can put a small paper-piece wetted by an aqueous STARCH's solution. Iodine's vapours will overcome onto the paper colouring itself in blackish hue. You confirmed iodine's volatility.
I hope this helps you.
2007-02-11 04:37:08
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answer #1
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answered by Zor Prime 7
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Acidified Hydrogen Peroxide
2017-01-18 03:10:08
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answer #2
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answered by ? 4
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Iodide ion is a reducing agent only, forcing the hydrogen peroxide to be an oxidising agent. Under aqueous conditions, iodine vapour cannot possibly be produced, but brown iodine solution instead.
H2O2 + 2H+ + 2e- ----> 2H2O
2I- ----> I2 + 2e-
If a gas is produced, it can only be by the separate catalytic decomposition of hydrogen perioxide:
2H2O2 ----> 2H2O + O2.
2007-02-11 04:57:59
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answer #3
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answered by Gervald F 7
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Hydrogen peroxide is strong oxidising agent.Its liberated
the nascent oxygen.react with potassium iodide,Iodine
gas will come.
2007-02-11 04:49:13
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answer #4
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answered by VENKATARAMAN K 2
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Oxygen
2007-02-11 04:23:37
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answer #5
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answered by Niks 3
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