(-1+3i)(6+i) = -9+19
Am I right?
2007-02-11 03:51:15 · 4 answers · asked by Anonymous in Education & Reference ➔ Homework Help
Using the FOIL (First, Outside, Inside, Last) method:
-1(6) -1(i) +18i +3i(i)
-6 -i +18i +3i^2
-6 +17i +3(-1) (remember, i = sqrt(-1) so i^2 = -1)
-6 +17i -3
17i - 9
2007-02-11 03:58:23 · answer #1 · answered by Grover 3 · 0⤊ 0⤋
Sorry, but that isn't right. Here is the problem worked out. Check and see where you went wrong. It is probably a simple addition error cause you are close.
(-1 + 3i)(6 + i); Use the FOIL method
(-1)(6) + (-1)(i) + (3i)(6) + (3i)(i)
-6 - i + 18i + 3i^2; The ^ symbol denotes an exponent
-6 +17i + (3)(-1); i^2 is defined as -1
-6 +17i -3
-9 + 17i
Hope this helped
10 pts best answer?
2007-02-11 04:42:46 · answer #2 · answered by ultrasonicsfreak 2 · 0⤊ 0⤋
i don't know i got 3i^2+17i-6
2007-02-11 03:56:56 · answer #3 · answered by greysgirl 3 · 0⤊ 0⤋
Yeah if iota = -6.48861 or 0.82195
;)
2007-02-11 04:13:24 · answer #4 · answered by Ω Nookey™ 7 · 0⤊ 1⤋