Question: the solar wind is a thin, hot gas given off by the sun. charged particles in this gas enter the magnetic field of the earth and can experience a magnetic force. suppose a charged particle traveling with a speed of 9.0e6 m/s encounters the earth's magnitude of 1.2e-7 T. assuming that the particle's velocity is perpendicular to the magnetic field at an altitude where the magnitude of 1.2e-7 T. assuming that the particle's velocity is perpendicular to magnetic field find the radius of...Find (a) an electron and (b) a proton
My Approach:
(a) electron
r = (9.11e-31)(9.0e6)/ (1.6e-19)(1.2e-7) = 427 m
(b) proton
r = (1.67e-27)(9.0e6)/ (1.6e-19)(1.2e-7) = 7.83e5 m
Book Answer: I don't have the answer to (a); however, for part (b) it is supposed to be 7.83e8 m. it's the reason why im posthing this question! appreciate the help
2007-02-11
03:45:40
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2 answers
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asked by
Jimmy
3
in
Science & Mathematics
➔ Physics