Solve by addition x+y=6,x-y=2 and 5x-3y=13,4x-3y=11?

Question

These are 4 different problems, and it says to solve the systems by addition

Answer 1

If you mean add all the equations together, then it would look like this:
x + y = 6
x - y = 2
5x - 3y = 13
4x - 3y = 11
-----------------

11x - 6y = 32

Hope that's what you needed!
oklahoma

Answer 2

Okay, your details aren't real clear, but I will assume you have two "problems" with two equations each.

So you simply add the equations together. They are both easy once you see how to do it.
x + y = 6 (given)
x - y = 2 (given)
------------
2x = 8 (add like variables in columns--x, y, and constants)
x = 4 (solve for x)
4 + y = 6 (substitute into either equation)
y = 2

Second system:

5x - 3y = 13 (given)
4x - 3y = 11 (given)

5x - 3y = 13 (still given)
-4x + 3y = -11 (multiply the 2nd equation by -1)
-------------------
x = 2 (add columns of like variables and constants)
4(2) - 3y = 11 (substitute back into an original equation)
8 - 3y = 11
-3y = 3
y = -1 (solve for y)

Answer 3

what are we solving for? and is that 1 problem, 2 or 4? you need to be more clear.

Answer 4

ok, first off, these are variables, not letters. so x+y=6 is rele anything u wana fill in, x=3, y=3, 3 plus 3 equals 6. now, figure out the others.