Physics Acceleration Problem?

Question

What is the acceleration of a 40-kg block of cement when pulled sidways with a net force of 200N?
Can anyone show me how to figure this out?

Answer 1

Find the acceleration (a) of a 40kg block of cement when pulled sideways with a net force (f) of 200N.

Solution (solve for a):
Force = mass X acceleration ====> f = ma.

Divide both sides of the equation by m.
f/m = a or a = f/m.

Substitute given values for f and m:
a = f/m
a = 200N / 40kg

200 N
--------- = a
40 kg
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
5 N
----- = a
kg
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
1kg•m
----------- = 1 Newton <==== NOTE
s²
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
5kg•m
---------- = a (kg cancel each other)
s²•kg
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
5 m
------ = a ****Answer**** or 5 m/s²
s²
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Answer 2

We know that, Force = (Mass) X (Acceleration)
So, substituting the values given for two variables in this equation, we can find out the value of the third quantity, the acceleration:
200 = 40 X (Acceleration)
So, Acceleration = 5 m/s^2

The acceleration will be along the same side (direction) in which the force is applied, according to Newton's Second Law of Motion.

Answer 3

Newt's 2nd Law: F=ma

a=F/m=200/40=5.0m/s^2

Answer 4

If the boy drops the ball to loose fall, right here would desire to stay with preliminary speed is 0 m/s very final speed is 14.7 m/s Acceleration is (gravity =9.8 m/s2) distance = a million/2 * gt^2 = a million/2 * 9.8 * 4 = 19.6 m If the boy means throws the ball with preliminary speed of 14.7 m/s, then right here would desire to stay with d = Vi *t + a million/2 gt^2 d= 14.7*2 + a million/2*9.8*4 = 40 9 m

Answer 5

F=ma

You want to find a
so you go: a=F/m
Since F=200N
and m=40kg

F/m=200/40=5

5m/s^2

Answer 6

devide the force by the mass