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simplify as much as possible
2x^2t^4 x 2t^8 x 7x

2007-02-11 01:21:05 · 7 answers · asked by I can help 1 in Science & Mathematics Mathematics

7 answers

To simplifiy fully, multiply the numbers together and add the exponents of common variables.

Numbers -------> 2*2*7 = 28
't' variable ------> t^4*t^8 = t^12
'x' variable ------> x^2*x = x^3

Thus, the final answer is:

28(x^3)(t^12)

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Hope this helps

2007-02-11 01:34:33 · answer #1 · answered by JSAM 5 · 0 1

Simplify: (2x^2) (t^4) (2t^8) (7x)

Group x terms together, group t terms together.
Multiply coefficients of like terms, & add exponents of like terms.
(2x^2)(7x) = 14x^3 <=== x terms
(t^4)(2t^8) = 2t^12 <=== t terms

Multiply coefficients together.
(14x^3)(2t^12) = (28x^3)(t^12) <=== Answer

2007-02-11 01:36:32 · answer #2 · answered by H. Scot 4 · 0 1

Rewriting you expression to make it a bit clearer:
(2)(x^2)(t^4)(2)(t^8)(7x)

the simplest form would be:
(28)(x^3)(t^12)

2007-02-11 01:52:22 · answer #3 · answered by urbanbard7 3 · 0 0

14x^3 x 2t^12
for x=2 and t=3 the answer is 119042784

2007-02-11 01:50:01 · answer #4 · answered by adamza 1 · 0 1

14x^3 X 2t^12

Thats the simplest form

2007-02-11 01:37:29 · answer #5 · answered by Aaron 4 · 0 1

First all terms must be grouped together, so that the numbers are all multiplied together. so are the x's and t's i.e

2*2*7* x^(2+1)*t^(4+8)
=28*x^3*t^12.
The rules of muliplying powers is that the values of the powers are added together.

2007-02-11 01:37:23 · answer #6 · answered by The exclamation mark 6 · 0 1

2x²t⁴x 2t^8 x 7x

28x³ t^12

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2007-02-11 03:31:10 · answer #7 · answered by SAMUEL D 7 · 0 0

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