To simplifiy fully, multiply the numbers together and add the exponents of common variables.
Numbers -------> 2*2*7 = 28
't' variable ------> t^4*t^8 = t^12
'x' variable ------> x^2*x = x^3
Thus, the final answer is:
28(x^3)(t^12)
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Hope this helps
2007-02-11 01:34:33
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answer #1
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answered by JSAM 5
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Simplify: (2x^2) (t^4) (2t^8) (7x)
Group x terms together, group t terms together.
Multiply coefficients of like terms, & add exponents of like terms.
(2x^2)(7x) = 14x^3 <=== x terms
(t^4)(2t^8) = 2t^12 <=== t terms
Multiply coefficients together.
(14x^3)(2t^12) = (28x^3)(t^12) <=== Answer
2007-02-11 01:36:32
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answer #2
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answered by H. Scot 4
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Rewriting you expression to make it a bit clearer:
(2)(x^2)(t^4)(2)(t^8)(7x)
the simplest form would be:
(28)(x^3)(t^12)
2007-02-11 01:52:22
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answer #3
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answered by urbanbard7 3
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14x^3 x 2t^12
for x=2 and t=3 the answer is 119042784
2007-02-11 01:50:01
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answer #4
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answered by adamza 1
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14x^3 X 2t^12
Thats the simplest form
2007-02-11 01:37:29
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answer #5
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answered by Aaron 4
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First all terms must be grouped together, so that the numbers are all multiplied together. so are the x's and t's i.e
2*2*7* x^(2+1)*t^(4+8)
=28*x^3*t^12.
The rules of muliplying powers is that the values of the powers are added together.
2007-02-11 01:37:23
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answer #6
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answered by The exclamation mark 6
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2x²t⁴x 2t^8 x 7x
28x³ t^12
- - - - - - -s-
2007-02-11 03:31:10
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answer #7
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answered by SAMUEL D 7
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