In what time after starting will the skier acquire a speed of 24m/s? Assume that the acceleration is constant and the path is straight?
2007-02-11 00:39:09 · 6 answers · asked by stephy 1 in Science & Mathematics ➔ Physics
v=24, t=t, u=0, a=g
t = (v-u)/a = 24/g
2007-02-11 01:39:27 · answer #1 · answered by avant1991 3 · 0⤊ 1⤋
Average velocity in example= 9/3 = 3 m/s
Final velocity in example=3*2=6 m/s
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Acceleration= 6/3= 2 m/s^2
To achieve 24 m/s, time taken= 24/2 = 12 s
For the above answers by other posters, average velocity is not equal to acceleration.
Unit for acceleration is m/s^2 by the way...
Acceleration is not g because it's not a free fall. Instead, from the calculations that i have, it's 2 m/s^2
2007-02-11 00:50:19 · answer #2 · answered by puakk 2 · 2⤊ 0⤋
If it takes 3 seconds to go 9 metres then he's going 3 metres in every second.
To travel 24 metres will take 8 seconds - 24 divided by 3
2007-02-11 00:41:55 · answer #3 · answered by Trevor 7 · 0⤊ 2⤋
Ted is correct even though Trevor had the right answer , his thinking is wrong. You need to find the acc. You have to divide the change in dist. over the change in time. 9m/3s.....So the acc is 3m/s2... Therefore your speed increases by 3m/s each sec so it will take 8 sec to reach 24 m/s.
2007-02-11 00:58:32 · answer #4 · answered by jay k 1 · 0⤊ 2⤋
v=24, t=t, u=0, a=g
t = (v-u)/a = 24/g
2007-02-11 00:44:02 · answer #5 · answered by SS4 7 · 0⤊ 2⤋
it will take him 8 seconds to reach 24m/sec
9m/3s = 3m/sec accleration
@2sec =6m/sec
@3sec = 9m/sec
@4sec = 12m/sec
@5sec = 15m/sec
@6sec = 18/m/sec
@7sec = 21m/sec
@8sec = 24m/sec
2007-02-11 00:50:59 · answer #6 · answered by Anonymous · 0⤊ 2⤋