jus solve the quadratic equation.
2007-02-10 23:24:04 · 9 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
x^2-2ax+a^2=0
x^2-ax-ax+a^2=0
x(x-a)-a(x-a)=0
(x-a)^2=0
x=a
2007-02-10 23:29:42 · answer #1 · answered by Anonymous · 2⤊ 0⤋
This is (x-a)^2=0 so x=a
2007-02-10 23:35:00 · answer #2 · answered by santmann2002 7 · 2⤊ 0⤋
Factor the equation:
(x - a)^2 = 0
(x -a)(x - a) = 0
x - a = 0 --> x = a
2007-02-10 23:28:16 · answer #3 · answered by Runa 7 · 1⤊ 0⤋
x² - 2ax + a² = 0
(x - a)(x - a) = 0
x = a
2007-02-10 23:40:50 · answer #4 · answered by Como 7 · 2⤊ 0⤋
you must recognize that the expression is
(x-a)^2 = x^2-2ax+a^2
So you see immediately tha x= a is the solution
2007-02-11 01:02:22 · answer #5 · answered by maussy 7 · 1⤊ 0⤋
verify with the discriminant if there are any roots.. 'a' is a fastened consistent regardless of order it would not have any roots, so there are not any ideas to this polynomial !!!
2016-10-01 23:11:06 · answer #6 · answered by mclelland 4 · 0⤊ 0⤋
(x-a)^2 = 0
x = a
2007-02-11 01:10:57 · answer #7 · answered by nayanmange 4 · 1⤊ 0⤋
x^2-2ax+a^2=0
x^2-ax-ax+a^2=0
x(x-a)-a(x-a)=0 (;ax*ax=a^2x^2 and -ax-ax=-2ax)\
(x-a) (x-a) = 0
x=a , x=a
2007-02-10 23:32:56 · answer #8 · answered by p 1 · 2⤊ 0⤋
(x-a)(x-a)=0
x=a
Check:
a^2-2a^2+a^2=0
a^2-a^2=0
0=0
I hope this helps!
2007-02-11 02:12:56 · answer #9 · answered by Anonymous · 0⤊ 0⤋