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1.How many moles of NH3 will be produced by the complete reaction of 5 moles of Hydrogen with Nitrogen?

2. How many moloes of Nitrogen are required?

if its possible can you show the process to get the answer

2007-02-10 21:58:51 · 2 answers · asked by aly 1 in Science & Mathematics Chemistry

2 answers

Lancenigo di Villorba (TV), Italy

The reaction involved is the following :

N2(g) + 3 H2(g) ---> 2 NH3(g)

This writing states the stiochiometric relations binding reactants and products. In this manner, you retrieve that 5 moles of hydrogen can form 3.333 moles of ammonia, as follows :
5 * 2 / 3 = 3.333 moles
where 2 and 3 are stoichiometric coefficients respectively for ammonia and hydrogen.
Similarly, you calculate the nitrogen's amount needed :
5 * 1 / 3 = 1.667 moles

I hope this helps you.

2007-02-10 22:30:14 · answer #1 · answered by Zor Prime 7 · 0 0

try loging onto weikipedia

2007-02-11 06:05:49 · answer #2 · answered by monalisa three 5 · 0 0

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