2007-02-10 21:17:36 · 14 answers · asked by Christian1234 1 in Science & Mathematics ➔ Mathematics
/sqrt (-49) = sqrt(-1 * 49)
= sqrt(-1) * sqrt(49)
= i * 7
= 7i
2007-02-10 21:21:55 · answer #1 · answered by wendywei85 3 · 1⤊ 1⤋
Express √-49 as a simplified complex number.
Under the radical sign, write -49 as (49)(-1):
√-49 = √[(49)(-1)]
*_______Note: √(a+b) = √a + √b
√[(49)(-1)] = (√49)(√-1)
√49 = ±7; therefore
(√49)(√-1) = ±7√-1
√-1 = i; therefore
±7√-1 = ±7i *****Answer*****
(The reason for the different answers to this question—some say the answer is 7i and some say the answer is ±7i—is that sometimes one forgets to include the negative result of taking a square root, like √49 = ±7......not +7 alone. Not taking into account the negative square root causes the bridge to collapse.)
2007-02-11 01:07:02 · answer #2 · answered by H. Scot 4 · 1⤊ 0⤋
sqrt(-49) = sqrt(49 * (-1)) = sqrt(49) * sqrt(-1) = 7i
"i" is so-called "imaginary one", a square root of (-1).
2007-02-10 21:22:43 · answer #3 · answered by vjstrugar 2 · 0⤊ 1⤋
i = sqrt(-1).
sqrt(-49)=sqrt(49 X-1)
=sqrt(49)Xsqrt(-1)
=+/- 7i
2007-02-10 21:42:42 · answer #4 · answered by pujja 2 · 0⤊ 0⤋
sqrt-49=i(sqrt49)=7i
2007-02-10 22:18:36 · answer #5 · answered by mradigan747 2 · 0⤊ 1⤋
enable x = a + ib a complicated decision hence x^40 9 = (a + ib)^40 9 for x^2 = a^2 - b^2 - 2abi enable x^4 = (m - ni)^4 the resultant no. will be authentic no. hence x^40 9 = p - qi a complicated no.
2016-12-04 00:57:34 · answer #6 · answered by Anonymous · 0⤊ 0⤋
√ (-49)= ± √(49 i²) = ± 7i
2007-02-10 21:31:19 · answer #7 · answered by Como 7 · 1⤊ 0⤋
7i
The i is an imaginary number that is the square root of -1. It's complex because it is composed of a real number, 7, and an imaginary number, i.
2007-02-10 21:21:56 · answer #8 · answered by Greg H 3 · 0⤊ 1⤋
Answer is : 7i , where : i = sqrt(-1)
2007-02-12 06:31:26 · answer #9 · answered by sandip s 1 · 0⤊ 1⤋
7i, where i=sqrt(-1)
2007-02-11 01:51:52 · answer #10 · answered by sushobhan 6 · 0⤊ 1⤋