Assume that a procedure yields a binomial distribution with n trials and the probablity of success for one trial is p. Given the values of n and p to find the mean u and standard deviation o. Find the minimum usual value u - 2o and the maximum usual value u + 2o.
n=1068 , p=2/3
2007-02-10 21:15:23 · 4 answers · asked by pooh 1 in Science & Mathematics ➔ Mathematics
The mean is simply np, or 712.
The standard deviation is sqrt(np(1-p)) = sqrt(237.333) = 15.405
So minimum usual value is 681.19 and maximum usual value is 742.81
2007-02-10 21:34:51 · answer #1 · answered by Mark P 5 · 0⤊ 0⤋
Mean u = np = 712
Standard deviation o = SQRT np(1-p) = 15.405
Min usual value = u - 2o = 742.81
Max usual value = u + 2o = 681.19
2007-02-11 05:31:32 · answer #2 · answered by Nimish A 3 · 0⤊ 0⤋
Why should I solve this for you? Are you taking a class? Does this class have a text and a teacher that give you procedures and examples?
2007-02-11 05:20:31 · answer #3 · answered by smartprimate 3 · 0⤊ 2⤋
What's this
2007-02-11 05:22:45 · answer #4 · answered by amitszonex 1 · 0⤊ 0⤋