Equation of vertical asymptote...
2007-02-10 21:10:36 · 9 answers · asked by Christian1234 1 in Science & Mathematics ➔ Mathematics
at x = 7 there is a vertical asymptote soi the equation for this asymptote is:
( and this should not be a surprise ) x = 7
aa you can see there is no y in it , that is normal for vertical asymtotes
2007-02-10 21:15:28 · answer #1 · answered by gjmb1960 7 · 0⤊ 0⤋
There will be a vertical asymptote when the denominator is equals to zero, so we have
( x + 1 )( x - 7 ) = 0
x = -1 or x = 7
2007-02-11 05:37:02 · answer #2 · answered by Anonymous · 1⤊ 0⤋
Finding vertical asymptote is at the denominator:
x+1=0
x-7=0
x=-1 and 7
2007-02-11 10:17:45 · answer #3 · answered by Anonymous · 0⤊ 0⤋
at x=7,there is a vertical asymptote so i the equation for this asymptote is x=7 as u can see there is no y in that is normal for vertical asymtotes
2007-02-11 05:24:47 · answer #4 · answered by SIVA RAM 1 · 1⤊ 0⤋
y = (x + 1) / (x + 1)(x - 7)
Equation of vertical asymptotes are x = 7, x = -1
ie function is not defined at x = -1 and x = 7
2007-02-11 05:36:26 · answer #5 · answered by Como 7 · 1⤊ 0⤋
y=(x+1)/(x+1)(x-7)=1/(x-7)
xy-7y=1
that means XY and 7Yare consigative numbers
2007-02-11 05:21:21 · answer #6 · answered by Manish G 2 · 0⤊ 0⤋
fdxcvxv
2007-02-11 05:19:34 · answer #7 · answered by Anonymous · 0⤊ 0⤋
I Don't no.
2007-02-11 05:18:58 · answer #8 · answered by amitszonex 1 · 0⤊ 0⤋
x=-1,7
2007-02-11 05:31:03 · answer #9 · answered by Anonymous · 1⤊ 0⤋