Number of zeros of the function y=2x^2 + 4x -3?

Answer 1

ANS. 2

EXPLANATION:
If
b^2 - 4ac = 0. Then roots = 1 and real
b^2 - 4ac < 0. Then roots = 2 but imaginary/complex numbers.
b^2 - 4ac > 0. Then roots = 2 and real

Here, b^2 - 4ac = 4^2 - 4*(2)*(-3) = 16 + 24 = 40 i.e. > 0.

Hence, roots are 2 and real.

Answer 2

To find number of zeros, consider 2x² + 4x - 3

This does not factorise so consider b² - 4ac:-

√(16 + 24) = √ 40

This is positive
ie there are two zeros of function y

Answer 3

Two.