x^2/3 -x -1/6 = 0
2007-02-10 20:12:40 · 6 answers · asked by Sam G 1 in Science & Mathematics ➔ Mathematics
If your first term is x to the 2/3 power, use a graphic method or successive approximation. Plot x^(2/3) and x+1/6 on the same graph and find the intersection.
If your first term is x squared over 3, then use the quadratic formula for ax^2+bx+c:
x = [-b ± √(b^2 - 4ac)]/2a where a = 1/3, b = -1 and c = -1/6
2007-02-10 20:20:17 · answer #1 · answered by gp4rts 7 · 0⤊ 0⤋
x=0
2007-02-11 04:19:55 · answer #2 · answered by elroloreversal 1 · 0⤊ 2⤋
As you have written it, the equation may be shown as:-
x^(2/3) - x - 1/6 = 0.
However , I have a funny feeling that you may mean:-
x² / (x-3) - x - 1/6 = 0 ?????
2007-02-11 06:10:17 · answer #3 · answered by Como 7 · 0⤊ 0⤋
x^2/3 - x = 1/6
x^2/3 ( 1 - x^1/3 ) = 1/6
So solve for:
x^2/3 = 1/6
and
1 - x^1/3 = 1/6
x^1/3 = 5/6
x^2/3 = 1/6
[x^2/3] ^ 3 = 1/6^3
x^2 = 1/216
sqrt [x^2] = sqrt [1/216]
x = 0.068 or 1/[6 sqrt6].
Do the same for the other
2007-02-11 05:00:21 · answer #4 · answered by bourqueno77 4 · 0⤊ 0⤋
The written equation is ambiguous (gp4rts is right). You need to use () to help clarify the equation.
2007-02-11 04:30:02 · answer #5 · answered by smartprimate 3 · 0⤊ 0⤋
the best is using numerical analysis.
2007-02-11 04:20:38 · answer #6 · answered by koki83 4 · 0⤊ 0⤋