2007-02-10 17:22:04 · 5 answers · asked by nurfan 1 in Science & Mathematics ➔ Chemistry
NaOH is a strong base and HCl a strong acid. Value of heat of neutralisation for a strong acid and a strong base is always 13.6 k.cal/mol or 57.3 kJ/mol.
2007-02-10 18:07:01 · answer #1 · answered by kavita b 2 · 1⤊ 0⤋
A question like this is generally part of a lab activity or is a question which follows others from which you can get the information you need to determine this value. If this is just a random, isolated question, I'd suggest that you just google "heat of neutralization NaOH HCl" and see what you come up with. Otherwise, you're going to need specific results from a calorimetry experiment or something else to determine that value...
2007-02-10 17:27:26 · answer #2 · answered by hcbiochem 7 · 0⤊ 0⤋
Because all neutralisation reactions boil down to the same overall equation, H+ + OH- ---> H2O, you might expect that the enthalpy of neutralisation of all acids and alkalis is the same, and, by and large, it is. The value is always around -57kJ/mol.
A negative sign is needed to show that the reaction is exothermic.
2007-02-10 19:43:07 · answer #3 · answered by Gervald F 7 · 0⤊ 0⤋
Heat Of Neutralization Table
2016-12-10 18:08:25 · answer #4 · answered by southern 4 · 0⤊ 0⤋
You could also calculate it using enthalpies (or heats) of formation and Hess's Law. You'll need to write a balance equation and then find a table of enthalpies of formation. The enthalpy of reaction is the sum of the products enthalpies of formation minus the sum of the reactants enthalpies of formation.
2007-02-10 17:54:38 · answer #5 · answered by jas 2 · 0⤊ 0⤋