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2007-02-10 17:08:10 · 3 answers · asked by ralphtips aj 1 in Science & Mathematics Mathematics

Hi thanks but ALL NUBERS USED HAVE TO BE A SINGLE DIGIT. SO THE NUMBER 11 DOESN'T WORK ANY (URGENT))

2007-02-10 17:36:12 · update #1

3 answers

Well, the factorization of 55440 is indeed 2*2*2*2*3*3*5*7*11.

This is a unique factorization, so you can complain all you want about not liking the 11 factor but that's just the way it is.

It is certainly interesting that 55440's factors include all the prime numbers up to and including 11, although it's not the first number with that distinction - that would be 2*3*5*7*11, or 2310.

55440 is a colossally abundant number.
http://mathworld.wolfram.com/ColossallyAbundantNumber.html

55440 is a superabundant number.
http://mathworld.wolfram.com/SuperabundantNumber.html

55440 is a superior highly composite number.
http://mathworld.wolfram.com/SuperiorHighlyCompositeNumber.html

If you're interested in what single-digit numbers can be evenly divided into 55440, that's a different question altogether.

1, 2, 3, 4, 5, 6, 7, 8, and 9 all go into 55440 evenly.

2007-02-10 17:47:20 · answer #1 · answered by Mark P 5 · 1 0

Prime factors of 55440 are : 2, 2, 2, 2, 3, 3, 5, 7, 11.

So: 55440 can be divided by any of those numbers AND any that you can make up by multiplying any of them together, such as the Douglas Adams number 42 (= 2 x 3 x 7) or
132 ( = 2 x 2 x 3 x 11), etc. You can of course find the other factors (co-factors?) corresponding to these by simply multiplying the remaining prime factors together. Example : 132 used up 2, 2, 3, and 11. So its co-factor contains 2, 2, 3, 5, and 7, whose product is : 420. Therefore 132 x 420 = 55440. (If you check that with your calculator, you'll find that it's correct.)

I hope this helps.

Live long and prosper.

2007-02-11 01:21:10 · answer #2 · answered by Dr Spock 6 · 0 0

55440/2=27720 so 2 is a factor
27720/2=13860 another 2
13860/2=6930 another 2
6930/2=3465 another 2
3465/5=693 so 5 is a factor
693/3=231 so 3 is a factor
231/3=77 another 3
2x2x2x2x5x3x3x7x11=55440

2007-02-11 01:31:04 · answer #3 · answered by rolifer@verizon.net 1 · 1 0

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