What's the equation?
If it's [1 1 A= [1 0
1 1] 0 1],
it's because to find the inverse of the first matrix, it's 1/ad-cb [-a c
b -d] and 1*1-1*1 equals 0, and anything over 0 is undefined.
EDIT: Oh I see what you are trying to do. Matrices don't come out nice on Yahoo! Answers.
2007-02-10 16:46:17
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answer #1
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answered by CB #7 ftw 3
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there is no equation that demands for a solution.
the only equation I see is A = [1 0 0 1]
so what is this ? a row vector called A nothing more nothing less
You ,meean this right ? and the solve A
[1 1 1 1] A = [1 0 0 1]
( T means transposed below )
a solution ( there are more is
A = [ (1,0,0,0)T, (0,0,0,0)T, (0,0,0,0)T,(1,0,0,0)T ]
i am unsure if you understand me so i wont bother to give you all solutions.
2007-02-10 18:31:57
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answer #2
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answered by gjmb1960 7
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Sorry, but you have not provided the equation.
The only thing which is seen is matrix A is a unit matrix.
2007-02-10 16:49:13
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answer #3
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answered by Tariq M 3
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That first matrix, with 1s in every position, has determinant zero which means that it's NOT invertible.
2007-02-10 17:12:43
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answer #4
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answered by modulo_function 7
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