simplifty: Write your answer without using negative exponents?

Question

(w^-7)^4

Answer 1

(w^-7)^4 = w^-28 or 1/w^28

Answer 2

1. A negative exponent indicates a fraction with the base raised to the abs val of the exponent in the denominator: (u^2)^-4 = u^(2*-4) = u^-8 = 1/(u^8) 2. This one is just pathetic: 6+(-6) = 6-6 = 0, and 0^2=0, so (6+-6)^2=0 Before getting freaked out by a problem that looks difficult, take a good look at it and try to find a way to make it simple. In this case, don't FOIL (6+-6), simplify it first and the problem becomes very easy to do. 3. 30w^2+15x^2+43xw-36w-3x+6

Answer 3

You really should read the previous answers before you continue asking questions; the answers are all there.

(w^-7)^4 = (1/w^7)^4 = 1^4 / (w^7)^4 = 1/w^28

Answer 4

Simplify: (w^-7)^4

First: when a variable has a negative exponent - make the variable a fraction > place the variable over 1......

(w^-7/1)^4

Sec: rule - exponents have to be positive > place the variable in the denominator....

(1/w^7)^4

Third: distribute the exponent "4" with the terms in parenthesis --- when you have a variable with an exponent raised to another exponent, multiply the exponents.....


(1^4/w^(7*4))

1/w^28

Answer 5

Since a^-x=1/a^x, you end up with (1/w^7)4. And because (a/b)^x=a^x/b^x, and (a^x)^y=a^(x*y), you get 1^4/w^28. Since 1*1*1*1 is obviously 1, you get 1/w^28. Thus, your answer is 1/w^28.

Answer 6

(1/w^7)^4 = 1/w^28

Answer 7

(w^-7)^4
=w^-28
=1/w^28

Answer 8

w^-a = 1/w^a

(w^-7)^4 = w^-28

1/w^28

Answer 9

1/(w^28)

Answer 10

Answer withdrawn.