wirte without parentheses?

Question

(b^3/-2a^4)^3

Answer 1

Simplify: (b^3/-2a^4)^3

First: distribute the exponent "3" with the term in the numerator....

*When you have a variable with an exponent raised to another - multiply the exponents....

b^(3*3)
b^9

Sec: distribute the exponent with the term in the denominator....

(- 2a^4)^3
- 2^3a^(4*3)
(-2)(-2)(-2)(a^12)
(-2)(4)(a^12)
- 8a^12

Third: combine the new results...

(b^9)/(- 8a^12)

Answer 2

You can take the top and bottom of the fraction to the 3rd power without changing the answer.

(b^3)^3 = b^9 because you multiply the two exponents.

-2 ^3 = -8

(a^4)^3 = a^12

So your answer is: b^9 / -8a^12

Answer 3

cube the top and the bottom and remember that when you raise a power to a power, the exponents multiply

b^3^3 = b^9
(-2a^4)^3 = -8a^12

b^9/-8a^12

Answer 4

The question you have can be:
(1) (b^3/-2(a^4))^3

or

(2) (b^3/(-2a)^4)^3

(m^z)^y = m^(z*y)

For (1):
(b^3/-2(a^4))^3 = b^(3*3)/(-2)^3.a^(4*3) = b^9/-8.a^12

For (2):
(b^3/(-2a)^4)^3 = b^(3*3)/((-2)^4.a^4)^3 = b^9/(16.a^4)^3 = b^9/4096.a^12

If the original question looks EXACTLY like your question (without any additional parentheses) then the answer is as in (1).

Answer 5

That's like (x/y)^3, which is x^3/y^3

So (b^3)^3 / (-2a^4)^3
= b^9 / -8a^12

Answer 6

Within brackets
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