Multiplying powers of a variable, you add the exponents:
x^a * x^b = x^(a+b)
So,
u^2 * u^5 * u^1 = u^(2+5+1) = u^8.
2007-02-10 16:00:08
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answer #1
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answered by Tim P. 5
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u^2 x u^5 x u=u^(2+5+1)=u^8
2007-02-10 16:20:44
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answer #2
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answered by yupchagee 7
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u^(2+5+1)
u^8
2007-02-10 15:58:54
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answer #3
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answered by radne0 5
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well, the properties of exponents is that when the bottom variables are the same and they are multiplied then you can add the exponents.
so, u^2*u^5*u^1 = u^(2+5+1) = u^8
2007-02-10 16:02:28
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answer #4
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answered by BIF 2
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u^ 8
2+5+1 = 8
product of exponents property * x^ a times x^ b = x ^ a+b
2007-02-10 16:26:14
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answer #5
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answered by rain7maker7 2
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hi, For this question, you would be able to desire to bear in mind that each and each time we've a similar bases, we are allowed to characteristic the exponents. for this reason, in maximum situations words we are able to assert: [ a^2 ][ a^2 ] = a^4 for this reason, on your subject, including the exponents supplies us: a million + 2 + 2 = 5 which could be utilized to grant us: [t]][t^2][t^3] = t^5 very final answer: t^5 i'm hoping that facilitates you out! Please permit me comprehend in case you have the different questions!
2016-11-03 03:09:03
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answer #6
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answered by Anonymous
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This is very simple. You add the exponents including the last one (whose exponent is 1). Which makes u^8.
2007-02-10 16:04:09
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answer #7
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answered by FLY PIG FLY! 2
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u^8
2007-02-10 15:59:31
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answer #8
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answered by Walking Man 6
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