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u^2 x u^5 x u

2007-02-10 15:55:42 · 8 answers · asked by I can help 1 in Science & Mathematics Mathematics

8 answers

Multiplying powers of a variable, you add the exponents:
x^a * x^b = x^(a+b)

So,
u^2 * u^5 * u^1 = u^(2+5+1) = u^8.

2007-02-10 16:00:08 · answer #1 · answered by Tim P. 5 · 1 0

u^2 x u^5 x u=u^(2+5+1)=u^8

2007-02-10 16:20:44 · answer #2 · answered by yupchagee 7 · 0 0

u^(2+5+1)
u^8

2007-02-10 15:58:54 · answer #3 · answered by radne0 5 · 2 0

well, the properties of exponents is that when the bottom variables are the same and they are multiplied then you can add the exponents.

so, u^2*u^5*u^1 = u^(2+5+1) = u^8

2007-02-10 16:02:28 · answer #4 · answered by BIF 2 · 0 0

u^ 8

2+5+1 = 8

product of exponents property * x^ a times x^ b = x ^ a+b

2007-02-10 16:26:14 · answer #5 · answered by rain7maker7 2 · 0 0

hi, For this question, you would be able to desire to bear in mind that each and each time we've a similar bases, we are allowed to characteristic the exponents. for this reason, in maximum situations words we are able to assert: [ a^2 ][ a^2 ] = a^4 for this reason, on your subject, including the exponents supplies us: a million + 2 + 2 = 5 which could be utilized to grant us: [t]][t^2][t^3] = t^5 very final answer: t^5 i'm hoping that facilitates you out! Please permit me comprehend in case you have the different questions!

2016-11-03 03:09:03 · answer #6 · answered by Anonymous · 0 0

This is very simple. You add the exponents including the last one (whose exponent is 1). Which makes u^8.

2007-02-10 16:04:09 · answer #7 · answered by FLY PIG FLY! 2 · 0 0

u^8

2007-02-10 15:59:31 · answer #8 · answered by Walking Man 6 · 0 0

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