2007-02-10 14:09:05 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Astronomy & Space
R=2*G*M/c^2 is the equation for the Schwarzschild radius. M=total mass inside the radius, G = Newton's gravitational constant, c=light velocity. If the density of the body is such that the body's radius is less than the Schwarzschild radius, that is a black hole. For a spherical mass of radius r and density m, the mass M = 4*π*r^3*m/3; thus r=cuberoot[3*M/4*π*m]; therefore
cuberoot[3*M/4*π*m] > 2*G*M/c^2; This comes out
M>√[3*c^6 / 23*π*m*G^3]
2007-02-10 14:16:47 · answer #1 · answered by gp4rts 7 · 0⤊ 0⤋
Again, what formula are you looking for.
Are you trying to figure the raidus of the Event Horizon, the mass, or what?
2007-02-10 14:34:57 · answer #2 · answered by Walking Man 6 · 0⤊ 0⤋
Any particular black hole?
2007-02-10 14:25:54 · answer #3 · answered by zahbudar 6 · 0⤊ 0⤋
There is no formula for it, Why do you ask one question several times?
2007-02-10 22:44:42 · answer #4 · answered by jhstha 4 · 0⤊ 0⤋
S=(Akc^3)/(4hG)
S-entropy
A-area of event horizon
k- Boltzmann constant
c- speed of light
h- Dirac's constant
G- gravitational constant
2007-02-10 16:40:13 · answer #5 · answered by futureastronaut1 3 · 0⤊ 1⤋
http://en.wikipedia.org/wiki/Black_hole#Mathematical_theory
2007-02-10 14:17:45 · answer #6 · answered by Anonymous · 0⤊ 0⤋
a+s=s lol
2007-02-10 14:17:50 · answer #7 · answered by ohmydrpepper 3 · 0⤊ 0⤋