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This is the question:
A certain first order reaction has a rate constant of .0275 at 20 degrees C. What is the value of k at 60 degrees C if the activation energy is 75.5 kj/mol.

So, K1 is .0275, k2 is unknown, T1 is 293 in kelvin, T2 is 333 k, and the activation energy is 75.5. I used this formula to solve the problem -
ln(k1/k2) = Ea/R (1/T2 - 1/t1)
So, (.0275/k2) = e to the ((75.5/8.31)((1/333)-(1/293)). then i got .0275/.9962, which is the wrong answer. The right answer is 1.1. Could someone please explain what I am doing wrong?

2007-02-10 13:25:10 · 1 answers · asked by Sam 3 in Science & Mathematics Chemistry

I did use R=8.31. Please try and show me work if you answer.

2007-02-10 14:25:40 · update #1

1 answers

Try using R as 8.314 J/(mole)(K) which is equivalent to what you used but with different units. You should have examples in your text where they work these problems, so you can see this.

Good luck.

2007-02-10 13:50:34 · answer #1 · answered by kentucky 6 · 0 0

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