Please Factor t^2+10t+16?

Answer 1

2 and 8 will make the middle term 10 and last term 16:
(t+2)(t+8)

I hope this helps!

Answer 2

The first thing I would do for this type of problem is to figure out what factors of 16 add up to get 10. If an answer doesn't come to you immediately, try listing the different factors of 16 on your paper.
They would be:
16 and 1
8 and 2
4 and 4

The two numbers that add up to 10 would therefore be 8 and 2. These are the numbers you want to use.

(t + 8) (t + 2) = t^2 + 10t + 16

You can check this answer or the answer you get by FOILing.
First
Outer
Inner
Last

Answer 3

Please Factor t^2+10t+16

First: multiply the 1st & 3rd coefficient to get "16." Find two numbers that give you "16" when multiplied & "10" (2nd/middle coefficient) when added/subtracted. The numbers are (8 & 2).

Sec: rewrite the expression with the new middle coefficients....

t^2 + 8t + 2t + 16

Third: when you have 4 terms --- group "like" terms & factor both sets of parenthesis....

(t^2 + 8t) + (2t + 16)

t(t + 8) + 2(t + 8)

= (t + 8)(t + 2)

Answer 4

(t+2)(t+8)

Answer 5

(t + 8) (t + 2)

Answer 6

(t + a)(t + b)
a + b = 10
ab = 16

(t + 8)(t + 2)