The length of a rectangular lot is 4 meters less than twice its width?

Question

The length of a rectangular lot is 4 meters less than twice its width, and the perimeter is 436 meters, find the length of the parking lot.

Please help thankyou1

Answer 1

L= 2w-4

L + L + W + W = 436
2W - 4 + 2W - 4 + W + W = 436
6W - 8 = 436
6W = 444
W= 74

L= 2(74) - 4
L= 144

Answer 2

"Allot" is supposed to be "quite a bit", for one factor. :) Now then! Permit me to provide an explanation for so it is no longer confusing! For #1, write an algebraic equation to precise the predicament. Considering there are 2 facets which might be quick, they each and every equal "x". As for the opposite 2, one is 5 meters greater than x, so that they each and every equal "x+5". Now put each side length together to make an equation: x+x+(x+5)+(x+5)=66. The opposite aspect equals sixty six because all of the aspects put together equal the perimeter. When simplified, this equation turns into 4x+10=66. Then just find x, which is 14. But you're not finished yet!!! Take into account that the difficulty says to seek out the size, now not simply in finding x!! But that is the handy section; simply fill within the x with 14. Do that process with #four, except put "4x-7" for the length of the parking lot. #three is also just a little difficult.... So, "x+10" is the aspect of the square, on account that the facet of the triangle is x (yup, an additional algebraic one). So that you can find the perimeter of the rectangular, multiply x+10 by four (which makes 4x+40). That implies that 4x+forty is 3 times the perimeter of the triangle(the perimeter is 3x, given that x is one part of the triangle, so 3 occasions that's 9x). Put together, this is 4x+forty=9x. This implies x is eight. The question asked to seek out the side of the triangle, which is x, so that you may discontinue there. Use this process to resolve #2, just keep in mind that #2 has a square & a rectangle, not a triangle.

Answer 3

The formula for Perimeter is:
2*Length + 2*width = Perimeter

Step 1: Draw a picture. Ok, I'm going to try to draw a picture for you on here to show you what is going on.
____________
|...........................|
|...........................| Length = 2*width - 4
|...........................|
|____Width___|



Step 2: Solve for Width. So, you have a parking lot with the length and the width labeled above. You are going to take the Perimeter's formula and fill in what you know.

2*Length + 2*Width = Perimeter (The Formula)

2*(2*W - 4) + 2*W = 436 (What I did here was filled in the length and width from the drawing, and perimeter given in the problem.)

4W-8 + 2W = 436 (Distribute)

6W = 444 (Collect like terms on both sides of the equation.)

W = 75 (Solve for W). This means that the width of the parking lot is 75 meters wide.



Step 3: Solve for Length. The problem asks for the length, so you are going to use this width, plug it back into the original perimeter equation, and solve for Length.

2L + 2W = Perimeter (Original Equation.)

2L + 2(74) = 436 (Plug in what you know. W = 74 from work done above, and 436 was given in the original problem.)

2L + 148 = 436 (Multiply.)

2L = 288 (move variables to one side of the equation)

L = 144 (Solve for L which equals to 144 meters.)

Your answer is Length is equal to 144 meters!

Answer 4

Answer: 144 meters

Explanation:
Let x = the width of the lot
2x - 4 = length
2(width) + 2(length) = Perimeter

2x + 2(2x - 4) = 436
2x + 4x - 8 = 436
6x - 8 = 436
6x = 444
x = 74

Length = 2x - 4
Length = 2(74) - 4
Length = 144

Answer 5

L = 2W - 4 M
W = Width
P = perimeter = 436 M
P = 2 W + 2 L = 436 M
P = 2 W + 2 L = 2W + 2(2W - 4 M) = 436 M
8W - 8 M= 436 M
8W = 444 M
W = 55.5 M
L: = 2 W - 4 M
L = 2 * 55.5 M - 4 M
L = 111 M - 4 M
L = 107 M

Answer 6

L=(2w-4)

divide the perimeter (436) by 2
436/2=218

218=2w-4 *subtract 4
214=2w *divide by 2
170=w

to find the length of the parking lot, subtract 170 from 218 (ex: 218-170=111)

L=111 meters

Answer 7

lenght is 144 meters
width is 74 meters

width + width -4 = length
74 +74 - 4 = 144

perimeter is 74 + 74 + 144 + 144

Answer 8

2 x length + 2 x width = 436m, so, 436m - 2 x length = 2xwidth. we also know that the length= 2x width - 4m. or putting it another way, 2 x width = length + 4m. since we have 2 equations that equal 2 x width we can combine the 2. 436m - 2 x length = 2x width = length + 4m, or 436m - 2 x length = length + 4m, subtract 4m from both sides of the = sign, 432m - 2x length= length. now we add 2 x length to both sides of the equation. 432m= 3 x length. length = 144m ftc

Answer 9

P=2l+2w
436=2(2w-4)+2w
436=4w-8+2w
436=6w-8
444=6w
74=w

l=2w-4
l=2(74)-4
l=148-4
l=144meters


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