13. A population of 2800 flowers is in Hardy-Weinberg equilibrium, and 2352 of them are red in color. The red allele [R]is the dominant allele; the allele for white color [r] is recessive. What would be the frequency of heterozygotes in the population?
A. .03
B. .16
C. .48
D. .71
E. .84
2007-02-10 06:49:47 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Biology
C. p^2+2pq+q^2=1
q^2=(2800-2352)/2800
q^2=448/2800
q=.4
p=.6
2pq=.48
2007-02-10 06:51:36 · answer #1 · answered by kz 4 · 0⤊ 0⤋
c.48
take total recessives, multiply by 2 because theres two alleles(rr). divide by 2800x2-the total alleles of the population. that gives you .4
in the equation psquared + 2pq +qsquared the 2pq is the heterozygotes. insert.4 in q and then .6 is p because they add to form 1 always. when you multiply .6x.4x2 it =.48
2007-02-10 08:17:44 · answer #2 · answered by wesnaw1 5 · 0⤊ 0⤋
C. .48
2007-02-10 07:00:11 · answer #3 · answered by deacon 6 · 0⤊ 0⤋