Thereare two elec.bulbs 60W,220V and 100W,220V. Which has the higher resistance?
2007-02-10 05:10:06 · 5 answers · asked by PLK 1 in Science & Mathematics ➔ Physics
Watt = volt * ampere
So for 60 watt bulb ampere = 60/220 =0.272727
And for 100 watt bulb ampere is =0.454545
Now Volt/Ampere = resistance
Hence Resistance is more for 60 watt bulb
2007-02-10 05:16:40 · answer #1 · answered by Mihir Durve 3 · 0⤊ 0⤋
Power = V^2/R (V=voltage, R=resistance)
Now multiply both sides by R and divide by P: R = V^2/Power
V=220 in both cases
Since power's in the denominator, the lower power gives more resistance, so it's the 60W bulb.
2007-02-10 05:44:39 · answer #2 · answered by lynxdaemon19 2 · 0⤊ 0⤋
The brighter bulb.
I did the same calculation but I dont' think it applies in this case. The resistance of the light is based off the filament inside the bulb. You would need to know what the material was and the cross sectional area to make that kind of calculation. But who knows maybe I'm wrong.
2007-02-10 05:19:44 · answer #3 · answered by pluto035 3 · 0⤊ 1⤋
100
2007-02-10 05:13:17 · answer #4 · answered by walter_b_marvin 5 · 0⤊ 2⤋
Higher resistance means less current. (E=I*R)
Less current means less power. (P=E*I)
2007-02-10 06:23:56 · answer #5 · answered by sojsail 7 · 0⤊ 0⤋