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x=65.5, x has a line over it. x=mean
What is the value of the middle of the interval?

2007-02-10 04:21:13 · 2 answers · asked by lil_one479 1 in Education & Reference Standards & Testing

2 answers

i think solution of this goes like this ..

first find the confidence interval , using this formula
x bar - t(alpha/2 , n-1) * s / sqrtn < u < x bar + t (alpha/2, n-1) *s / sqrt n ...
where n -1 is degree of freedom ( df) and alpha /2 = 5%/2 = 2.5%
use student t distribution table for calculation t ( alpha/2 , n-1)
.and after getting confidence interval..calculate middle term ..

hope this will help you
regards
rakesh gupta

2007-02-11 07:33:12 · answer #1 · answered by RAKESHtutor 3 · 0 0

- I did no such thing! I swear I was somewhere else at the time and it was in fact the one who posts just after me that did the deed!

I've never been so insulted in all my life. Okay, I have but thats between me and my therapist.

I just figured you needed some intermission till someone had a valid answer. If you laughed - my job is done. If not..., there are no refunds. Sorry.

2007-02-10 04:47:51 · answer #2 · answered by Victor ious 6 · 0 0

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