He records the length as 5.34 m and the breadth as 7.19 m. What would be the “best” value which could be given for the area of the plot?
2007-02-10 04:21:04 · 4 answers · asked by TP 1 in Science & Mathematics ➔ Physics
The other guy gave the right answer. I am adding details. Multiplying the two you get 38.3946 M squared. Using significant digit rules, you only have three significant digits. Only the first three digits are considered good or usable. That rounds to 38.4 M squared.
2007-02-10 04:34:31 · answer #1 · answered by Jack 7 · 1⤊ 0⤋
38.4 sq metres
2007-02-10 07:44:17 · answer #2 · answered by Anonymous · 0⤊ 0⤋
38.4 sq metres
2007-02-10 04:28:56 · answer #3 · answered by mainwoolly 6 · 1⤊ 0⤋
38.4 m² is correct but I would say the 'best' value would be :-
414 ft² ... sounds bigger !!
2007-02-10 06:58:06 · answer #4 · answered by Norrie 7 · 1⤊ 1⤋