does the bouyant force on it increase or remain unchanged?
2007-02-10 03:17:00 · 10 answers · asked by greenbeast 1 in Science & Mathematics ➔ Physics
buoyant force = weight of the displaced fluid.
Although the pressure on the stone increases as it descends, for all practicle purposes, it is incompressible at the pressures in the lake and therefore the volume of the stone remains unchanged.
Although the pressure on the fluid increases, I think it's also safe to say it's density stays the same.
The weight of the displaced fluid is a function of the density of the fluid and the volume displaced.
If you assume those two are constant, then the buoyant force is also constant.
2007-02-10 03:22:58 · answer #1 · answered by Dr W 7 · 3⤊ 0⤋
The buoyant force acting on the object is equal to the weight of the liquid displaced by the object. Once the stone is fully submerged, the buoyant force will remain unchanged because the volume of water that it displaces will remain unchanged. This is assuming that the temperature of the water throughout the lake is constant and therefore the density of the water is constant.
2007-02-10 03:28:07 · answer #2 · answered by tashley235 3 · 0⤊ 0⤋
An object is bouyant upward equal to the WEIGHT of the water displaced. As you go deeper and deeper down, the WEIGHT DISPLACED of the water DOES NOT INCREASE because it is INCOMPRESSABLE . Water is not a gas, and it is for all practical purposes incompressable. Therefore it density per cubic foot or meter doesnt change any appreciable amount.
The bouyant force remains the same.
2007-02-10 03:27:39 · answer #3 · answered by James M 6 · 0⤊ 0⤋
Water density does not change with pression, so the bouyant force on the stone will remain the same, according to Arquimedes principle (force = weight of the volume of the liquid displaced)
2007-02-10 03:32:21 · answer #4 · answered by Jano 5 · 0⤊ 0⤋
Both.
If you think simply on Archimedes's law, the depth does not have influence. Therefore buoyant force remains unchanged.
By the other side, density increases with the depth, because pressure increases too. The the buoyant force also increases. This change is very small, in a lake there will be no difference.
2007-02-10 03:29:30 · answer #5 · answered by Javier 2 · 0⤊ 0⤋
I don't know, but if I were thrown into a deep lake, I sure as heck wouldn't be bouyant -- I'd be pissed.
The buoyant force equals the weight of the fluid displaced.
Once completely displaced, it's done.
2007-02-10 03:24:11 · answer #6 · answered by OriginalSim 3 · 0⤊ 0⤋
No, the bouyant rigidity on an merchandise relies upon upon the quantity of the water displaced via the item. this won't replace via fact the item maintains to sink. The rigidity interior the water will improve somewhat via fact the item sinks, yet shouldn't replace the bouyant foce.
2016-11-03 01:52:42 · answer #7 · answered by Anonymous · 0⤊ 0⤋
the buoyancy of something would only change if it were to take on water. as for a rock it would not take on much water as it is solid. that depends on the structure of the rock as to how much water it can take on. also if you dip a sponge in the water would the water it hold be a part of the sponge? as this is how you would know if the rock is changing because if you consider the rocks new form of water content (or is it new buoyancy)? the real new question is what type of rock? and it it takeing new form? also what is the water content(95%H2O 5% other) and what would be te other? so realy this is however most would dissagree an unknowen answer. you would need to hold a poll on this quetion in this form. its like saying 2a-5b=123.4 what is A when you don't know B LOL. figure that out.
2007-02-10 03:34:36 · answer #8 · answered by dudedawg20 3 · 0⤊ 1⤋
Since water is not compressible, it will weigh the same even at deep places .... The buoyancy will be the same.
2007-02-10 03:47:40 · answer #9 · answered by Gene 7 · 0⤊ 0⤋
Increase...duh thats like first grade stuff....
2007-02-10 03:19:44 · answer #10 · answered by Anonymous · 0⤊ 3⤋