How did you get those index signs right?
Anyways,
a>
Since (x-2) squared =9,
(x-2) either equals 3 or it equals negative 3
If x-2=3
=> x=5,
else x=2-3=-1
Thus, x= 5 or -1
b>
if2(x+1)(3-x)=0
either (x-1) equals zero, or (3-x) equals zero, because the only way product of 3 quantities can be zero is if either of them is zero, or both are zero.
So x+1=0,
=>x=-1
or x=3
So, x= 3 or neg.1
2007-02-10 01:18:44
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answer #1
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answered by shrek 5
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a) |x-2| = 3
x-2=3
x=5
or
x-2=-3
x=-1
b) x+1=0
x=-1
or
3-x=0
x=3
2007-02-10 09:15:21
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answer #2
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answered by ghsalamatbashi2000 2
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a)x=5 (5-2)^2 = (3)^2 = 9
b) x=3 or x = (-1) 2(3+1)(3-3)= 2 x 4 x 0 = 0
2((-1+1)(3-(-1)) =2 x 0 x 4 =0
2007-02-10 09:14:34
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answer #3
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answered by rrohret2 2
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Question a)
(x - 2)² = 9
x - 2 = 3 , - 3
x = 5 , -1
Question b)
2(x + 1)(3 - x) = 0
(x + 1)(3 - x) = 0
x = -1, 3
2007-02-10 10:46:33
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answer #4
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answered by Como 7
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a) |x-2|=3
which means
x-2=3 x=5
or
x-2=-3 x=-1
b)x+1=0 x=-1
or
3-x=0 x=3
2007-02-10 09:10:19
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answer #5
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answered by Ioana 2
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A. x^2-4x+4=9; x^2-4x-5=0; (x+1)(x-5)
B. 2x+2(3-x)=0; 6x+6-2x^2-2x=0; -2x^2+4x+6=0; 2x^2-4x-6=0; (2x+2)(x-3)
2007-02-10 09:20:25
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answer #6
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answered by Burton Dude 2
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(x - 2)² = 9
(x - 2)(x - 2) = 9
x² - 2x - 2x + 4 = 9
x² - 4x + 4 = 9
x² - 4x + 4 - 9 = 9 - 9
x² - 4x - 5 = 0
x² + x - 5x - 5
x(x + 1) - 5(x + 1)
(x - 5)(x + 1)
- - - - - - - - -s-
2007-02-10 10:26:07
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answer #7
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answered by SAMUEL D 7
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(x-2)^2=9
(X-2)^2-9=0
(X-11)(X+7)=0
THEREFORE,
X=11,7
2(X+1)(3-X)=0
THEREFORE,
X=-1,3
2007-02-10 09:11:58
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answer #8
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answered by jonny k 3
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